Little Johnnie pees out 0.25L of a 2.50 mol/L of urine solution. The public pool's final volume is 4.60x10^6 L. Assuming Little Johnnie is the only kid that peed that
day (unlikely), what is the dilute concentration of urine in the public pool? *
a. 2.2x10-6 mol/L
b. 4.6x105 mol/L
c. 1.4x10-7 mol/L
Option 1

atomic mass = 39

number of neutrons = 20

number of protons= 19

electronic configuration = 1s2 2s2 2p6 3s2 3p6 4s1

the number of electron in first shell = 2

number of electrons in n=3 shell = 8

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.