A) If a student has 5.6 moles of sodium, how many moles of chlorine gas are needed to fully react with the sodium?
Given: Na(s)+ Cl2(g)= NaCl
b) If I have 6.8mol of Cl2 and 5.6mol Na, which will be the limiting reagent?

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally