Using the periodic table, explain the difference between hydrogen, deuterium, and tritium - i. e. hydrogen-1, hydrogen-2, and hydrogen-3.
a) allotropes vary in their number of protons - so they contain 1, 2, and 3 protons, respectively.
b) the atoms deviate in their number of photons - so they contain 1, 2, and 3 photons, respectively.
c) isotopes differ only in their number of neutrons - so they contain 0, 1, and 2 neutrons, respectively.
d) these configurations diverge in their number of electrons - so they contain 1, 2, and 3 electrons, respectively.

C) Isotopes differ only in their number of neutrons - so they contain 0, 1, and 2 neutrons, respectively.

Explanation: Isotopes are elements which have same atomic number but different mass number. Hydrogen has three isotopes named as hydrogen , deuterium , and tritium .

Atomic number= number of protons = number of electrons (for neutral atom)

Mass number = number of protons + number of neutrons

Thus Number of neutrons = Mass Number - Atomic number

Thus number of neutrons in hydrogen with atomic number 1 and mass number 1 = 1 - 1 = 0

Thus number of neutrons in deuterium with atomic number 1 and mass number 2 = 2 - 1 = 1

Thus number of neutrons in tritium with atomic number 1 and mass number 3 = 3 - 1 = 2

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.