For the rxn CaCo3(s)+2Hcl(aq)_CaCl(aq)+Ca2(g)+H 2O(l)68.1 g solid CaCo3 is mixed with 51.6Hcl what number of grams of Co2 will be produced

29.9 g of CO₂ will be produced by the reaction.

Explanation:

This is the reaction:

CaCO₃(s)  + 2HCl (aq)  →  CaCl₂(aq)  + CO₂(g) +  H₂O(l)

First of all, we state the moles of each reactant:

68.1 g . 1mol/ 100.08g = 0.680 mol of carbonate

51.6 g . 1 mol/36.45g = 1.46 mol of acid.

The solid salt is the limiting reactant. Ratio is 2:1

2 moles of acid can react to 1 mol of salt

1.46 mol of acid may react with (1.46 . 1)/2 = 0.727 moles

As we only have 0.680 moles of salt, we do not have enough.

Let's work at the product side. Ratio is 1:1

1 mo of salt can produce 1 mol of gas

0.680 moles will produce 0.680 moles of gas

We convert the moles to mass → 0.680 mol . 44g / 1mol = 29.9 g of CO₂

adding or remove a gaseous reactant or product changes the concentrations. if the concentration of reactant or product is increased, the system will shift away from the side in which concentration was increased (i.e. if the concentration of reactants is increased, the system will shift toward the products. if more products are added, the system will shift to form more reactants). conversely, if the concentration of reactant or product is decreased, the system will shift toward the side in which concentration was decreased (i.e. if reactants are removed, the system will shift to form more reactants. if the concentration of products is decreased, the equilibrium will shift toward the products).

explanation:

pie chart because it is in percents ( % )