A weather balloon has at 27.0 C , 1.00 atm, with an initial volume of 2.00 liters is released into the atmosphere where the temperature is -23.0 C and the pressure is 0.500 atm.

3.41

Explanation:

(1.00atm) (2.00 L) /(27.0C) = (.500atm) (x)/ (-23.0C)

This is how you set it up because P1V1/T1 = P2V2/T2.

Then you can cross multiple, all units except Liters will cancel and you can solve for x and have your answer.  

the dependant variable is spilled water

the independent is the heat

your answer is c) plasma

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