The rate constant for a particular zero-order reaction is 0.075 M s-1. If the initial concentration of reactant is 0.537 M it takes s for the concentration to decrease to 0.100 M.

It takes 5.83s to decrease the concentration of the reactant from 0.537M to 0.100M

Explanation:

A zero-order reaction follows the equation:

[A] = [A]₀ - kt

Where [A] is actual reaction of the reactant = 0.100M

[A]₀ the initial concentration = 0.537M

k is rate constant = 0.075Ms⁻¹

And t is time it takes:

0.100M = 0.537M -0.075Ms⁻¹t

-0.437M = -0.075Ms⁻¹t

5.83s = t

It takes 5.83s to decrease the concentration of the reactant from 0.537M to 0.100M

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.

the answer is c i believe