N2+3H2=>>2NH3. If 6.72dm³ of each of Nitrogen and hydrogen (measured at S. T.P.) are made to produced Ammonium. Which of the reacted will be in excess and by how many moles?

Hydrogen, 0,2 mol

Explanation:

= 22, 4 l/mol

V () = 6,72 = 6,72 l

V () = 6,72 = 6,72 l

The formula is:

n =

n  () = 6,72l /22,4 l/mol = 0,3 mol

n  () = 6,72l /22,4 l/mol = 0,3 mol (the same)

But from the equation we get a proportion that 1 mol  () - 3 mol ()

(we have more hydrogen than is need for the reaction)

So there is excess of

We only need   = 0,1 mol ()

0,3 mol (hydrogen quantity we have) - 0,1 mol (hydrogen quantity we need for the reaction) = 0,2 mol (excess)

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periodic trends is an atom that gets larger as the number of electronic shells increase, the radius of atoms increases as you go down a certain group in the periodic table of elements. in general, the size of an atom will decrease as you move from left to right of a certain period.