Liquid hexane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 17.2 g of hexane is mixed with 19. g of oxygen. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction. Be sure your answer has the correct number of significant digits.

16.5g of CO₂ could be produced

Explanation:

The combustion of hexane occurs as follows:

C₆H₁₄(l) + 19/2O₂ → 6CO₂ + 7H₂O

Where 1 mole of hexane reacts with 19/2 moles of O₂.

To solve this question we need to find the moles of each reactant in order to find limiting reactant. The moles of the limiting reactant will determine the moles of CO₂ produced:

Moles C₆H₁₄ -Molar mass: 86.18g/mol-:

17.2g hexane * (1mol / 86.18g) = 0.200 moles hexane

Moles O₂ -Molar mass: 32g/mol-:

19g O₂ * (1mol / 32g) = 0.594 moles oxygen.

For a complete reaction of 0.594 moles of oxygen are required:

0.594 moles O₂ * (1mol C₆H₁₄ / 19/2 moles O₂) = 0.0625 moles C₆H₁₄.

As there are 0.200 moles of hexane, hexane is the excess reactant and oxygen the limiting reactant.

The moles of CO₂ produced assuming a yield of 100% -All moles of oxygen react producing carbon dioxide.:

0.594 moles O₂ * (6mol CO₂ / 19/2 moles O₂) = 0.375 moles of CO₂ could be produced. The mass is:

0.375 moles of CO₂ * (44.01g / mol) =  

it is the most commonly accepted one

answer: cellular respiration takes in food and uses it to create atp, a chemical which the cell uses for energy. usually, this process uses oxygen, and is called aerobic respiration. it has four stages known as glycolysis, link reaction, the krebs cycle, and the electron transport chain.