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Chemistry, 13.02.2021 07:50 adejumoayobami1
When 6.853 mg of a sex hormone was burned in a combustion analysis, 19.73 mg of CO2 and 6.391 mg of H2O were obtained. What is the empirical formula of the compound? (My book says that the answer is C19H30O2, but I can’t figure out how they got this answer!)
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When 6.853 mg of a sex hormone was burned in a combustion analysis, 19.73 mg of CO2 and 6.391 mg of...
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