What volume will 1.25 liters of carbon dioxide occupy at 50.0ác if the pressure changes from 0.865 atm to 0.820 atm?

1.76
.567
1.18
1.32

             1.32 L

              According to Boyle's Law, " The Volume of a given mass of gas at constant temperature is inversely proportional to the applied Pressure". Mathematically, the initial and final states of gas are given as,

                                     P₁ V₁  =  P₂ V₂     (1)

Data Given;

                  P₁  =  0.865 atm

                  V₁  =  1.25 L

                  P₂  =  0.820 atm

                  V₂  =  ??

Solving equation 1 for V₂,

                   V₂  =  P₁ V₁ / P₂

Putting values,

                   V₂  =  (0.865 atm × 1.25 L) ÷ 0.820 atm

                   V₂  =  1.318 L ≈ 1.32 L

          As the Pressure has decreased from 0.865 atm to 0.820 atm, therefore, Volume got increased from 1.25 L to 1.32 L.

the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3