2) 2HF + C₂O₄²⁻ ⇔ 2F⁻ + H₂C₂O₄ K= 0.24
Chemistry, 10.02.2021 19:50 CamBroOkaii2590
Given the reactions:
1) HF ⇔ H⁺ + F⁻ K= 6.8 x 10⁻⁴
2) 2HF + C₂O₄²⁻ ⇔ 2F⁻ + H₂C₂O₄ K= 0.24
Determine the value of the equilibrium constant for the reaction:
3) H₂C₂O₄ ⇔ 2H⁺ + C₂O₄²⁻
Answers: 2
Chemistry, 22.06.2019 15:30
The identities of substances are the same before and after which type of change
Answers: 1
Chemistry, 22.06.2019 16:30
For the reaction shown, calculate how many moles of no2 form when each of the following completely reacts. 2n2o5(g)→4no2(g)+o2(g) part a 1.0 mol n2o5 express your answer using two significant figures. nothing mol m o l request answer part b 5.4 mol n2o5 express your answer using two significant figures.
Answers: 2
Chemistry, 23.06.2019 09:00
The vapor pressure of water at 25.0°c is 23.8 torr. determine the mass of glucose (molar mass = 180 g/mol) needed to add to 500.0 g of water to change the vapor pressure to 22.8 torr.
Answers: 1
Given the reactions:
1) HF ⇔ H⁺ + F⁻ K= 6.8 x 10⁻⁴
2) 2HF + C₂O₄²⁻ ⇔ 2F⁻ + H₂C₂O₄ K= 0.24
2) 2HF + C₂O₄²⁻ ⇔ 2F⁻ + H₂C₂O₄ K= 0.24
Mathematics, 03.02.2021 21:50
English, 03.02.2021 21:50
Mathematics, 03.02.2021 21:50
Physics, 03.02.2021 21:50
Chemistry, 03.02.2021 21:50
Mathematics, 03.02.2021 21:50
Mathematics, 03.02.2021 21:50
Spanish, 03.02.2021 21:50
Mathematics, 03.02.2021 21:50