NEED HELP ASAP A gas occupies a volume of 560 cm at a temperature of 120 °C. To what temperature
must the gas be lowered if it is to occupy 400 cm?

7.56°C is the temperature when the gas occupies 400cm³

Explanation:

Based on Charles's law, the volume of a gas is directly proportional to its absolute temperature under constant pressure. The equation is:

V₁T₂ = V₂T₁

Where V is volume and T is absolute temperature of 1, initial state and 2, final state of the gas.

Computing the values:

V₁ = 560cm³

T₂ = ?

V₂ = 400cm³

T₁ = 120°C + 273.15 = 393.15K

560cm³*T₂ = 400cm³*393.15K

T₂ = 280.71K - 273.15 =

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