2. How many grams of AlCl3 can be prepared from 3.50 liters of HCl gas? 1 point
E. 6.9 L AlCl3
F. 13.9 g AlCl3
G. 6.94 g AlCl3
H. 0.314 g AlCl3

by cartels in other countries, shipped by air, mail, or land. i cant really see your answer choices : /

what does the table look like

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer

answerlinnaeus;