When vinegar is added to some marble chips ( calcium carbonate) bubbles of gas are observed, what gas is produced and how can it be identified?

By passing the gas through lime water

Explanation:

The equation of the reaction of vinegar with  calcium carbonate in the form of marble chips is shown below;

CaCO3(s) + 2CH3COOH(aq) > Ca(CH3COO)2(aq) + H2O(l) + CO2(g).

We can see from the reaction equation that the gas produced is carbon dioxide. This gas is identified by passing the gas through lime water. If lime water turns milky, then the gas is truly carbon dioxide.

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"

the ozone layer acts as a filter for the shorter wavelength and highly hazardous ultraviolet radiation (uvr) from the sun, protecting life on earth from its potentially harmful effects. when the sky is clear, there is an inverse relationship between stratospheric ozone and solar uvr measured at the earth's surface.