Draw a mechanism for the reaction of water with formic acid. In the box to the left, draw any necessary curved arrows. Show the products of the reaction in the box to the right. Include any nonzero formal charges and all lone pairs of electrons. Finally, indicate which side of the reaction is favored at equilibrium.

See explanation

Explanation:

When water reacts with formic acid, The following equilibrium is set up;

HCOOH(aq) + H20(l) ⇄ HCOO-(aq) + H30+(aq)

This is because, the water abstracts a proton from formic acid to form its conjugate base, formate ion.

At equilibrium,  the forward is favored.

It’s b. mass i searched it up

For cyclohexane compounds drawn in a chair conformation:   -axial bonds are vertical  -equatorial bonds are parallel to two bonds within the ring.  thus, as i assume the chair conformation is drawn:   -the x group is in an axial position, as are the five other vertical bonds.  -three axial bonds are on the top face of the ring  -the other three axial bonds are on the bottom face  the position of the second substituent on each ring carbon is equatorial.  gauche groups must be on an adjacent carbon such as carbon 6 and carbon 2, and also gauche groups are rotated by 60 degrees relative to each other.  drawing the newman projections for c1–c2 and c1–c6 aids in visualizing the groups that are gauche to the y group on c1.  click this link and watch some academic videos that may you more understand the topic