Astudent used a dcp solution (standardized to 9.98x10-4m) to analyze a sample of extract from 2.50g of solid food. the titration required 22.49ml of dcp. 87.00% of all the ascorbic acid in the food was collected in the extract. (mm ascorbic acid = 176.124 g/mol)
what mass of food (in grams) would be required to attain the rda of ascorbic acid (60 mg)

Given that the molarity of DCP equals 9.98x10-4M. And it used to analyze a sample of extract from 2.50g of solid food. The titration required 22.49mL of DCP. 87.00% of all the ascorbic acid in the food was collected in the extract.

 Amount of solid = 60 mg AA (100mg/87mg)(1g/1000mg)(1 mol AA/176.124 gAA)(1mol DPC/1mol AA)( 1L DCP/9.98x10-4mol DPC)(2.50g solid/0.02249 L DPC) = 43.6 g solid.

answer; /// i do believe that the correct answer is (a) boiling

c. heat could easily travel through the molecules in the air and escape/enter the flask. removing the air slows down the heat transfer.