A sample of nitrogen gas contains 8.23 x 10^23 molecules. What is the volume of this sample at STP? Please show and explain the steps.

30.6 L

Explanation:

Given data:

Number of molecules of nitrogen = 8.23×10²³ molecules

Volume occupy at STP = ?

Solution:

Standard temperature = 273.15 K

Standard pressure = 1 atm

One mole of any substance at STP occupy 22.4 L volume.

Number of moles of nitrogen:

1 mole contain 6.022×10²³ molecules.

8.23×10²³ molecules × 1mol / 6.022×10²³ molecules

1.37 mol

Volume of nitrogen:

1.37 mol × 22.4 L / 1 mol

30.6 L

c8h10 is your answerr

the answer is b. dilution