How many moles of NaCl are in 2.35 liters of a 4.67 M solution?

There are 10.97 moles of NaCl in 2.35 liters of a 4.67 M solution.

no. of moles = volume × molarity

no of moles = 2.35L × 4.67M

no of moles = 10.97mol

Therefore, there are 10.97 moles of NaCl in 2.35 liters of a 4.67 M solution.

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Explanation:

Molarity by definition is number of moles per liter. You could set up the dimensional analysis or just use the formula. If you multiply the two values, the liters will cancel, and you will get moles of sodium chloride.

n = 10.97 moles ; we are only good till two sig figs. You could round up to 11.0, but that's up to on how accurate you want to be

the objects have the same charge.