How many moles of NaCl are in 2.35 liters of a 4.67 M solution?

There are 10.97 moles of NaCl in 2.35 liters of a 4.67 M solution.

no. of moles = volume × molarity

no of moles = 2.35L × 4.67M

no of moles = 10.97mol

Therefore, there are 10.97 moles of NaCl in 2.35 liters of a 4.67 M solution.

Learn more about no. of moles at: link

Explanation:

Molarity by definition is number of moles per liter. You could set up the dimensional analysis or just use the formula. If you multiply the two values, the liters will cancel, and you will get moles of sodium chloride.

n = 10.97 moles ; we are only good till two sig figs. You could round up to 11.0, but that's up to on how accurate you want to be

a. they are both space stations

happy to

pls mark as brainliest.

alkaline metals are lithium, sodium, rubidium, potassium, cesium and francium.

alkali metals have electronegativity from 0.7 to 1, lowest in periodic table of elements, which means that alkali metals (i group in periodic table) has positive oxidation number in compounds.

electronegativity is a chemical property that describes the tendency of an atom to attract a shared pair of electrons towards itself.

alkaline metals (far left in main group) have lowest ionizations energy and easy remove valence electrons,

for example, potassium is the alkali metal and has a single valence electron in the outer electron shell.

electron configuration of potassium is: ₁₉k 1s²2s²2p⁶3s²3p⁶4s¹.

they can not exist alone in nature, because they are very reactive.