The stock concentration of NaOH is 0.5M. 0.5M = 0.500mol/1.0L. a) Calculate the mole of NaOH required to prepare 200mL of 0.5M solution.
b) How many grams of NaOH required from the number of mole of NaOH that you calculate from9a. The MW of NaOH = 40.0g/mol
c)Calculate % (m/v) of NaOH from the above. m/v means mass of solute/100mL of solution. Hint: The amount of gram calculated above is based on 200 mL, how many grams should be if you only have 100mL
d) Assume the density of NaOH is 1.00g/mL How much water is required to be added to prepare the above solution? Remember your total volume is 200 mL.

As light moves from one material into the next, which of the following affects how much the light waves will refract, or bend? angle at which the ray strikes the medium color of the material density of the material temperature of the light wave

Under what conditions will a gas be most likely to exhibit the ideal gas properties predicted by the ideal gas law? 1)high pressures and high temperature, because particles are forced closer together with higher kinetic energy, so intermolecular forces of attraction are weaker 2)high pressure and low temperature, because particles are forced closer together and moving slower, so the volume of the particles is less significant 3) low pressure and high temperature, because particles are spread farther apart and moving faster, so the intermolecular forces of attraction are weaker 4)low pressure and low temperature, because particles are spread farther apart with lower kinetic energy, so the volume of the particles is less significant

Which of the following are acids or bases? 1. sodium hydrogen 2. barium hydroxide solution 3. carbonate solution