When determining the density of a grape, a student was not careful when putting the grape into the graduated cylinder, and some of the water got splashed out. How would that affect the determined density of the grape? In other words, is the calculated density be higher or lower than the actual density of the grape? Explain your answer (fill in the blanks below). If some of the water got splashed out, the measured “grape + water” volume is incorrectly (high or low?).
Then the calculated volume of the grape (“grape+water” – “water only” volume) is incorrectly (high or low?).
When calculating the density, the mass is divided by a (higher or lower?) value. As the result, the determined density is erroneously (high or low?) and therefore the determined density is (higher or lower?) than the actual density of the grape.