If 35.5 grams of calcium oxide react with excess water, how many grams of calcium hydroxide can be formed?
CaO + H2O - Ca(OH)2

Mass of Ca(OH)2= 46.916 g

Given

Reaction

CaO + H2O - Ca(OH)2

Required

mass of Ca(OH)2

Solution

Mol of CaO :

= mass : MW

= 35.5 g : 56 g/mol

= 0.634

From the equation , mol ratio CaO : Ca(OH)2 = 1 : 1, so mol Ca(OH)2 = 0.634

Mass Ca(OH)2 :

= mol x MW

= 0.634 x 74

= 46.916 g

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