7. How many moles 02 can be produced from 4.3 moles of N205 in the reaction 2N205(g) ---> 4NO2(g) + O2(g) mole ratio is 1mole 02/ 2 moles N205
A. 2.2 mol
B. 8.6 mols
C. 17.2 moles
D. 1.2 mol

A) 2.2 mol

Explanation:

Given data:

Number of moles of O₂ produced = ?

Number of moles of N₂O₅ decomposed = 4.3 mol

Solution:

Chemical equation:

2N₂O₅    →   4NO₂ + O₂

Now we will compare the moles of N₂O₅ and O₂.

            N₂O₅       :        O₂

             2            :         1

            4.3         :       1/2×4.3 = ×2.2

Thus, from 4.3 moles of  N₂O₅ 2.2 moles of O₂ are produced.