At what temperature would 2.10 moles of Nitrogen gas have a pressure of 1.25 atm and in a 25.0 L tank? (Hint: R = 0.082 L atm K−1 mol−1) Don't spam!!!

Given :-Moles = 2.10Gas = NitrogenPressure = 1.25 atmVolume = 25LTo Find :-TemperatureSolution :-

As we know that

PV = nRT

Here,

P = PressureV = Volumen = MolesT = Temperature

According to the question,

1.25 × 25 = 2.1 × 0.082 × T31.25 = 2.1 × 0.082 × T31.25 = 1.722T31.25/0.1722 = T181 ≈ T

Temperature is 181 K