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2KCIO3 → 2KCI + 302
How many grams of potassium chloride are produced if 52 g of potassium chlorate decompose?

A )32 g KCI
B )19 g KCI
C)44 g KCI
D)1.5 g KCI

Mass of KCl : 32 g

Given

Reaction

2KCIO₃ → 2KCI + 30₂

52 g Potassium chlorate

Required

Mass of KCl

Solution

mol of KCIO₃ :

= mass : MW

= 52 g : 122.55 g/mol

= 0.424

From equation, mol KCl :

= 2/2 x mol KCIO₃

= 2/2 x 0.424

= 0.424

Mass KCl :

= mol x MW

= 0.424 x 74.5513 g/mol

= 31.6≈32 g

the answer is:  

line graphs show patterns in data with variables that change over time; whereas, circle graphs show data as parts out of a whole (such as out of 100%).

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally