Draw the products of the following reactions: Part A There is a scheme of a reaction between two compounds, which react in the presence of PdL2 and (CH3CH2 )3 N. The first compound consists of CH double bond CH. The first (from left to right) carbon has a CH3 group attached above the plane of the bond. The second carbon has an I atom attached below the plane of the bond. The second compound is a line-angle structure consisting of two carbon atoms in the chain, with a double bond between the carbons and a C triple bond N group attached.

explanation: no but i do not usually comment

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole