Consider the compound chloroform. It's percent composition is 10.06% carbon, 0.85% hydrogen, and 89.09% chlorine. Thx molar mass of
chloroform is 119.5 g/mol. What is the coefficient found to calculate the
molecular formula for chloroform?

the answer is   c.) 1575 j.

explanation:

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally