How many grams of Fe are needed to create 32.5mol Fe3O4?

5444.89 grams of Fe

Explanation:

1) We need the chemical equation for Fe3O4 to find the mole ratio for Fe to Fe3O4. Chemical equation:

3Fe+4H2O → Fe3O4+4H2

The mole ratio of Fe to Fe3O4 is 3:1

2) Now, we find how many grams of Fe are needed to produce 32.5 moles of Fe3O4.

= 97.5 moles Fe needed to produce 32.5 moles of Fe3O4

3) Convert 97.5 moles of Fe into grams. The molar mass of Fe is 55.845g.

= 5444.8875g or 5444.89g.

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.

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