If 50.0g of kcl reacts with 50.0 g of 02 to produce KCLO3 according to the following equation, how many grams of kclo3 will be formed

Mass = 82.11 g

Explanation:

Given data:

Mass of KCl = 50.0 g

Mass of O₂ = 50.0 g

Mass of KClO₃ produced = ?

Solution:

Chemical equation:

2KCl + 3O₂   →     2KClO₃

Number of moles of KCl:

Number of moles = mass /molar mass

Number of moles = 50.0 g/ 74.5 g/mol

Number of moles = 0.67 mol

Number of moles of O₂:

Number of moles = mass /molar mass

Number of moles = 50.0 g/ 32 g/mol

Number of moles = 1.56 mol

Now we will compare the moles of oxygen and KCl.

          O₂          :          KClO₃

            3           :             2

           1.56       :          2/3×1.56 = 1.04 mol

        KCl          :          KClO₃

            2           :             2

           0.67       :         0.67

Number of moles of KClO₃ formed by KCl are less thus, it will act as limiting reactant.

Mass of KClO₃:

Mass = number of moles × molar mass

Mass = 0.67 mol ×122.55 g/mol

Mass = 82.11 g

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