The activation energy of a reaction is 55.8 kJ/mol and the frequency factor is 1.5×10^11/s. Calculate the rate constant of the reaction at 24 ∘C

23.0 s⁻¹ is rate constant

Explanation:

Using the Arrhenius equation:

k = A * e^(-Ea/RT)

Where k is rate constant

A is frequency factor (1.5x10¹¹s⁻¹)

Ea is activation energy = 55800J/mol

R is gas constant (8.314J/molK)

And T is absolute temperature (24°C + 273 = 297K)

Replacing:

k = 1.5x10¹¹s⁻¹ * e^(-55800J/mol/8.314J/molK*297K)

k = 1.5x10¹¹s⁻¹ * 1.53x10⁻¹⁰

the answer is 75.0%.

it’s previous models   because when i picked that son of a gun’s answer it was wrong look for previous models because they might make it a different letter