Anyone Know the equations? Iron
iron (III) chlorate solid decomposes into iron (III) chloride solid and oxygen gas equation

  2Fe(ClO₃)₃    →   2FeCl₃  + 9O₂

Explanation:

To solve this problem, we need to first identify the reactants and products in this problem.

 The reactant is iron (III) chlorate

        product is iron (III) chloride and oxygen gas

So the chemical formula:

    iron (III) chlorate  = Fe(ClO₃)₃

    iron (III) chloride  = FeCl₃

    oxygen gas  = O₂

Therefore:

           Fe(ClO₃)₃    →   FeCl₃  + O₂

We need to balance this expression:

          2Fe(ClO₃)₃    →   2FeCl₃  + 9O₂

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.