Determine the number of representative particles in each substance. a. 4.45 mol of C6H1206
b. 0.250 mol of KNO3
c. 2.24 mol of H2
d. 9.56 mol of Zn

A. The number of particles in 4.45 moles of C₆H₁₂O₆ is 2.68×10²⁴ particles.

B. The number of particles in 0.250 mole of KNO₃ is 1.51×10²³ particles.  

C. The number of particles in 2.24 moles of H₂ is 1.35×10²⁴ particles.

D. The number of particles in 9.56 moles of Zn is 5.76×10²⁴ particles.

From Avogadro's hypothesis, we understood that:

1 mole of any substance = 6.02×10²³ particles

With the above information in mind, we can obtain the answers to the questions as follow:

A. Determination of the number of particles in 4.45 moles of C₆H₁₂O₆.

1 mole of C₆H₁₂O₆ = 6.02×10²³ particles

Therefore,

4.45 moles of C₆H₁₂O₆ = 4.45 × 6.02×10²³

4.45 moles of C₆H₁₂O₆ = 2.68×10²⁴ particles

B. Determination of the number of particles in 0.250 mole of KNO₃

1 mole of KNO₃ = 6.02×10²³ particles

Therefore,

0.250 mole of KNO₃ = 0.250 × 6.02×10²³

0.250 mole of KNO₃ = 1.51×10²³ particles

C. Determination of the number of particles in 2.24 moles of H₂

1 mole of H₂ = 6.02×10²³ particles

Therefore,

2.24 moles of H₂ = 2.24 × 6.02×10²³

2.24 moles of H₂ = 1.35×10²⁴ particles

D. Determination of the number of particles in 9.56 moles of Zn

1 mole of Zn = 6.02×10²³ particles

Therefore,

9.56 moles of Zn = 9.56 × 6.02×10²³

9.56 moles of Zn = 5.76×10²⁴ particles

Learn more about Avogadro's number:

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a) 26.79 * 10^23 particles

b) 1.51  * 10^23 particles

c) 13.5 * 10^23 particles

d) 57.6 * 10^23 particles

Explanation:

a) 1 mole of a substance contains 6.02 * 10^23 particles

4.45 mol of C6H1206 contains 4.45 * 6.02 * 10^23 particles = 26.79 * 10^23 particles

b) 1 mole of a substance contains 6.02 * 10^23 particles

0.250 mol of KNO3 contains 0.250 * 6.02 * 10^23 particles = 1.51  * 10^23 particles

c)  1 mole of a substance contains 6.02 * 10^23 particles

2.24 mol of H2 contains 2.24 * 6.02 * 10^23 particles = 13.5 * 10^23 particles

d) 1 mole of a substance contains 6.02 * 10^23 particles

9.56 mol of Zn contains  9.56 * 6.02 * 10^23 particles= 57.6 * 10^23 particles

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%

i think the answer is terrae but not 100 percent sure. ▓▬▬ §