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Chemistry, 29.01.2021 04:10 daniel1480
How many moles of HCI would be needed to completely use up 5.8 moles of Al? 2A1 + 6HCI -> 2AlCl3 + 3H2
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How many moles of HCI would be needed to completely use up 5.8 moles of Al?
2A1 + 6HCI -> 2AlCl3...
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