How many grams of calcium hydroxide must react to give 3.09 g of ca3(po4)2?
na3po4(aq)+ca(oh)2(aq)→ca3(po4)2(s) +naoh(aq)

Molar mass:

Ca(OH)₂ = 74.093 g/mol
Ca₃(PO₄)₂ = 310.17 g/mol

Mole ratio:

2 Na₃PO₄ + 3 Ca(OH)₂ = Ca₃(PO₄)₂ + 6 NaOH

3 x 74.093 g Ca(OH)₂ 310.17 g Ca₃(PO₄)₂
            ?? g Ca(OH)₂ 3.09 g Ca₃(PO₄)₂

Mass of Ca(OH)₂ = 3.09 x 3 x 74.093 / 310.17

Mas of Ca(OH)₂ = 686.84211 / 310.17

= 2.214 g of Ca(OH)₂

hope this helps!

Acovalent bond is formed between the two hydrogen bonds

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