What is the theoretical yield of Ca(OH)2, in grams, if 31.8 g of CaO is hydrolyzed (reacted) in an excess of water?

The theoretical yield of Ca(OH)₂ : 42.032 g

Given

31.8 g of CaO

Required

The theoretical yield of Ca(OH)₂

Solution

Reaction

CaO + H₂O⇒Ca(OH)₂

mol CaO (MW=56 g/mol) :

= mass : MW

= 31.8 g : 56 g/mol

= 0.568

From equation, mol Ca(OH)₂ = mol CaO = 0.568

Mass Ca(OH)₂ (MW=74 g/mol) :

= 0.568 x 74

= 42.032 g

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