How many grams of copper (II) fluoride (CuF2) are needed to make 9.66 liters of a 2.73 M solution?

Mass of Copper (II) fluoride needed = = 2677.87 g

Given

9.66 L of 2.73 M Copper (II) fluoride

Required

Mass

Solution

Molarity : mol solutes per liters of solution

M = n : V

n = mol solute

V = volume of solution

mol Copper (II) fluoride :

= M x V

= 2.73 M x 9.66 L

= 26.3718 mol

Mass Copper (II) fluoride :

= mol x MW CuF₂

= 26.3718 mol x 101,543 g/mol

= 2677.87 g

answer:

the answer is 6 valence electrons.

explanation:

valence is the # of electrons on the outer most shell of an atom.

oxygen has 6.

although, the valency of oxygen is 2, because it only needs to make 2 covalent bonds, or gain 2 electrons, to achieve the stable octet configuration of a noble gas.

that's it!

if you need further assistance, let me know: )

~ trueboss72