A 1.018 g sample pure platinum metal was reacted with HCl to form 1.778 g of a compound containing only platinum and chlorine. Determine the empirical formula of this "Pt-Cl" Compound.

Explanation:

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In this case, since HCl and Pt react according to the following chemical equation:

Whereas PtClx is the compound containing Pt and Cl; thus, since 1.018 g out of 1.778 g correspond to Pt and therefore 0.760 g to chlorine, so we determine the empirical formula of this compound by firstly computing the moles of each element:

Now, we divide the each moles by those of Pt as the fewest ones in order to compute their subscripts in the empirical formula:

Thus, the required formula is:

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b) mutualism

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