If 4 moles of O2 and 8 moles of N2 occupy a 12 L container at a pressure of 6 atm, what is the partial
pressure of N2?

P(N₂) = 4.02 atm

Explanation:

Number of moles of O₂ = 4 mol

Number of moles of N₂ = 8 mol

Total pressure = 6 atm

Partial pressure of N₂ = ?

Solution:

We will calculate the partial pressure by using mole friction.

P(N₂) = X(N₂)P(total)

X(N₂) = mol friction = moles of N₂ / total number of moles

X(N₂) = 8 mol / 12 mol = 0.67

Partial pressure of N₂:

P(N₂) = X(N₂)P(total)

P(N₂) = 0.67 × 6 atm

P(N₂) = 4.02 atm

i would say b

explanation:

but i think i would need more information than that