Biological half-life of medicine works in the same way as radiological half-life. Acetaminophen (Tylenol) has a biological half-life of about 2 hours (though it varies depending on individual metabolism). What percentage of your original dosage remains in your system after 6 hours when you are allowed to take another dose?

12.5%

Explanation:

From the question given above, the following data were obtained:

Half-life (t½) = 2 h

Time (t) = 6 h

Percentage remaining =.?

Next we shall determine the number of half-lives that has elapse. This can be obtained as follow:

Half-life (t½) = 2 h

Time (t) = 6 h

Number of half-lives (n) =?

n = t / t½

n = 6/2

n = 3

Finally, we shall determine the percentage of original dosage remaining as follow:

Amount remaining (N) = Original amount (N₀) /2ⁿ

N = N₀ / 2ⁿ

Divide both side by N₀

N/N₀ = 1/2ⁿ

Input the value of n i.e 3

N/N₀ = 1/2³

N/N₀ = 1/8

N/N₀ = 0.125

Multiply by 100 to express in percent.

N/N₀ = 0.125 × 100

N/N₀ = 12.5%

Thus, percentage of original dosage remaining is 12.5%

it should be p1 v1 = p2 v2

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