HELP!! 75 pts A 12.00 gram sample of a crude ore contains 2.89 % HgS. What is the percentage of mercury in the ore? (2.49)

The percentage of mercury in the ore : 2.49%

Given

12 g of sample

2.89% HgS

Required

The percentage

Solution

mass of HgS in the ore :

= 2.89% x 12 g

= 0.3468 g HgS

Mass of Hg in HgS :

= (Ar Hg/MW HgS) x mass HgS

= (200.592/232,66 g/mol) x 0.3468

= 0.299 g

% mercury (Hg) in sample(a crude ore) :

= (0.299 g : 12 g) x 100%

= 2.49%

practical process described pest part of scientific investigation.

because practical knowledge is powerful then therotical knowledge.

you did not give any options thus this is the best answer i can give to you with this little information you have given

> they are both natural and not man made

> they can be tracked and predicted by the right tools

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