Using the mass of baking soda that you used this lab, calculate the theoretical (expected) yield of NaCH3COO in grams ? Mass of baking soda - 4.5 g

4.4 g

Explanation:

The equation of the reaction is;

NaHCO3 (aq) + CH3COOH (aq) > CO2 (g) + H2O (l) + CH3COONa (aq)

Mass of baking soda - 4.5 g

Molar mass of NaHCO3 = 84.007 g/mol

Number of moles of baking soda= 4.5 g/84.007 g/mol = 0.0536 moles

If 1 mole of NaHCO3 yields 1 mole of CH3COONa

0.0536 moles of NaHCO3 also yields 0.0536 moles moles of CH3COONa

Hence;

Theoretical yield of CH3COONa =  0.0536 moles * 82.0343 g/mol = 4.4 g

i don't see a text, but i am gonna assume this *orbit* the curved path, usually elliptical, described by a planet, satellite, spaceship, etc., around a celestial body, as the sun.

the seeing the electronic configuration we can say that the element is fluorine.

fluorine is the most electronegative element in the periodic table.

but by only seeing the configuration we cannot say about its reactivity because we don't know if its configuration after excitation or by addition of electrons.

but if not then, it is the lightest halogen and exists as a highly toxic pale yellow diatomic gas at standard conditions. as the most electronegative element, it is extremely reactive: almost all other elements, including some noble gases, form compounds with fluorine.