A stock solution of Al(CH3COO)3 is available to prepare solutions that are more dilute. Calculate the volume, in mL, of a 2.0-M solution of Al(CH3COO)3 required to prepare exactly 250 mL of a 0.230-M solution of Al(CH3COO)3.

Explanation:

= Initial concentration = 2 M

= Final concentration = 0.23 M

= Initial volume

= Final volume = 250 mL

We have the relation

So, the required volume is .

neutrons are in the middle of the atom and the electrons, which are much smaller.

each chemical family is represented as a group or column on the periodic table. based on chemical properties, there are 6 types of chemical families. group 1 represents alkali metals, group 2 represents alkaline earth metals, groups 3 to 12 represent transition metals, groups 13 to 16 represent non-metals and other metals, group 17 represents halogens and group 18 represents noble gases.