Chemistry, 21.01.2021 22:20 Jennifer312332
A 0.380 g sample of an unknown monoprotic acid is titrated with 0.300 M KOH to the equivalence point. It requires 20.1 mL of KOH to reach this point. Elemental analysis is also performed, showing that the acid contains 1.6% H, 22.2% N, and 76.2% O. Use this information to determine the molecular formula and the molar mass of the unknown acid.
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A 0.380 g sample of an unknown monoprotic acid is titrated with 0.300 M KOH to the equivalence point...
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