What is the molarity of a solution with 1.43 moles of sodium chloride in 0.875 liters of solution?

1.63 M

Math

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Chemistry

Unit 0

Aqueous Solutions

Step 1: Define

1.43 mol NaCl (sodium chloride)

0.875 L solution

Step 2: Find M

Step 3: Check

Follow sig fig rules and round. We are given 3 sig figs.

1.63429 M ≈ 1.63 M

answers: to make sure that all of the broken pieces of tablet were added to the water, to allow for fair comparison of all three trials, with different particle sizes to avoid experimental error

the answer is c. nacl