If a small weather balloon with a volume of 58.0 L at a pressure of 1.00 atmosphere was deployed at the edge of Typhoon Odessa, what was the volume of the balloon when it reached the center

final volume is 60.42 L

Explanation:

given data

initial volume v1 = 58 L

pressure P1 = 1 atm

we take P2 = 40 mbar

solution

we get here final volume

so p2 = 1 - 40 ×  = 0.96 atm

so

p1 × v1 = p2 × v2    .........1

so put here value

58 × 1 = v2 × 0.96

solve it we get

v2 = 60.42 L

the reaction mixture contains some ammonia, plus a lot of unreacted nitrogen and hydrogen. the mixture is cooled and compressed, causing the ammonia gas to condense into a liquid. the liquefied ammonia is separated and removed. the unreacted nitrogen and hydrogen are then recycled back into the reactor .

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :