Item 9 A sample of CaCO3 (molar mass 100. g) was reported as being 30. percent Ca. Assuming no calcium was present in any impurities, the percent of CaCO3 in the sample is

The percent of CaCO₃ in the sample is 75%.

Explanation:

We can find the percent of CaCO₃ in the sample knowing that 30 g of Ca are present in 100 g of CaCO₃.

First, we need to find the number of moles of Ca, and since the ratio of Ca in CaCO₃ is 1:1 we can find the percent of CaCO₃ in the sample as follows:

Now, the mass of CaCO₃ is:

Finally, the percent of CaCO₃ in 100 g of the sample is:                                        

Therefore, the percent of CaCO₃ in the sample is 75%.

I hope it helps you!                

why is cellular respiration important for homeostasis?

it changes food into energy that the organism can use.

which of the following is most likely to happen if a cell is not able to divide?

the cell will not be replaced when it is damaged.

explanation: