The density of water at 60.0 °C is 0.9832 g/mL. If the specific gravity of acetic acid is 1.023 at 60.0 °C, what is the density of acetic acid at 60.0 °C?

1.0058 g/mL

Explanation:

Note: Specific gravity of a substance is same as the relative density.

R.D = Density of the substance/ Density of water.

R.D = D/D' Equation 1

Make D the subject of the equation

D = R.D×D' Equation 2

Where R.D = Specific gravity of acetic acid, D = density of acetic acid, D' = density of water.

At 60°C,

R.D = 1.023, D' = 0.9832 g/mL

Substitute into equation 2

D = (1.023×0.9832)

D = 1.0058 g/mL

Hence the density of acetic at 60°C is  1.0058 g/mL

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