Methanol can be produced by the following reaction: CO(g) 2 H2(g) CH3OH(g). How is the rate of disappearance of hydrogen gas related to the rate of appearance of methanol

Explanation:

Hello!

In this case, for the reaction:

In such a way, via the rate proportions, that is written considering the stoichiometric coefficients, we obtain:

Whereas the reactants, CO and H2 have negative stoichiometric coefficients; therefore the rate of disappearance of hydrogen gas is related to the rate of appearance of methanol as shown below:

Which means that the rate of disappearance of hydrogen gas is negative and the rate of appearance of methanol is positive.

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