Calculate the number of oxygen atoms in a 50.0 sample of dinitrogen tetroxide . Be sure your answer has a unit symbol if necessary, and round it to significant digits.

1.309 x 10^24 oxygen atoms

Explanation:

Molar mass of N2O4,=  2 x Molar mass of Nitrogen + 4 x Molar mass of Oxygen

= 2 x 14.01 + 4 x 16.0

= 92.02 g/mol

One mole of a substance is equal to 6.022 × 10²³ unit/ atoms/ molecules

In N2O4, there are 4  moles of Oxygen

if 92.02 g contains = 4 x 6.022 x 10 ^23 molecules

50.0 g wll contain=  (4 x 6.022 x 10 ^23  x 50)/ 92.02g

1.309 x 10^24 oxygen atoms

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explanation:

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2