Acetylene gas, C2H2, reacts with oxygen according to the following equation. If 52.0 g of acetylene react completely with sufficient oxygen, how many grams of carbon dioxide are produced

176 g of CO₂.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2C₂H₂ + 5O₂ —> 4CO₂ + 2H₂O

Next, we shall determine the mass of C₂H₂ that reacted and the mass of CO₂ produced from the balanced equation.

This is illustrated below:

Molar mass of C₂H₂ = (2×12) + (2×1)

= 24 + 2 = 26 g/mol

Mass of C₂H₂ from the balanced equation = 2 × 26 = 52 g

Molar mass of CO₂ = 12 + (2×16)

= 12 + 32 = 44 g/mol

Mass of CO₂ from the balanced equation = 4 × 44 = 176 g

From the calculations made above,

52 g of C₂H₂ reacted to produce 176 g of CO₂.

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !