The amount of calcium hydroxide needed to react completely with 100.0g of nitric acid

The amount of Calcium hydroxide : = 58.719 g

Given

100 g Nitric Acid-HNO₃

Required

The amount of Calcium hydroxide

Solution

Reaction(balanced) :

Ca(OH)₂ (s) + 2HNO₃ (aq) → Ca(NO₃)₂ (aq) + 2H₂O (l)

mol of Nitric acid (MW 63 g/mol) :

mol = mass : MW

mol = 100 : 63

mol = 1.587

From the equation, mol ratio of Ca(OH)₂ : HNO₃ = 1 : 2, so mol Ca(OH)₂ :

=1/2 x mol HNO₃

= 1/2 x 1.587

=0.7935

Mass of Ca(OH)₂ (MW=74 g/mol) :

= mol x MW

= 0.7935 x 74

= 58.719 g

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